Base | Representation |
---|---|
bin | 1100010010111011110… |
… | …1111111011011010111 |
3 | 202012020202221222022102 |
4 | 3010232331333123113 |
5 | 11430110244300043 |
6 | 241013140152315 |
7 | 21155521163003 |
oct | 3045675773327 |
9 | 665222858272 |
10 | 211241400023 |
11 | 81650299445 |
12 | 34b3439869b |
13 | 16bc6267974 |
14 | a31d06d703 |
15 | 57652e96b8 |
hex | 312ef7f6d7 |
211241400023 has 4 divisors (see below), whose sum is σ = 211246419528. Its totient is φ = 211236380520.
The previous prime is 211241400017. The next prime is 211241400089. The reversal of 211241400023 is 320004142112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211241400023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211241399968 and 211241400004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211241420023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2446088 + ... + 2530973.
It is an arithmetic number, because the mean of its divisors is an integer number (52811604882).
Almost surely, 2211241400023 is an apocalyptic number.
211241400023 is a deficient number, since it is larger than the sum of its proper divisors (5019505).
211241400023 is an equidigital number, since it uses as much as digits as its factorization.
211241400023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5019504.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 211241400023 its reverse (320004142112), we get a palindrome (531245542135).
The spelling of 211241400023 in words is "two hundred eleven billion, two hundred forty-one million, four hundred thousand, twenty-three".
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