Base | Representation |
---|---|
bin | 1100010010111100010… |
… | …1000000101001111001 |
3 | 202012020220102110100211 |
4 | 3010233011000221321 |
5 | 11430111232140212 |
6 | 241013243431121 |
7 | 21155542625353 |
oct | 3045705005171 |
9 | 665226373324 |
10 | 211243240057 |
11 | 81651335933 |
12 | 34b34b254a1 |
13 | 16bc6760345 |
14 | a31d3cc0d3 |
15 | 576555e9a7 |
hex | 312f140a79 |
211243240057 has 2 divisors, whose sum is σ = 211243240058. Its totient is φ = 211243240056.
The previous prime is 211243240051. The next prime is 211243240079. The reversal of 211243240057 is 750042342112.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 179355638016 + 31887602041 = 423504^2 + 178571^2 .
It is a cyclic number.
It is not a de Polignac number, because 211243240057 - 211 = 211243238009 is a prime.
It is not a weakly prime, because it can be changed into another prime (211243240051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105621620028 + 105621620029.
It is an arithmetic number, because the mean of its divisors is an integer number (105621620029).
Almost surely, 2211243240057 is an apocalyptic number.
It is an amenable number.
211243240057 is a deficient number, since it is larger than the sum of its proper divisors (1).
211243240057 is an equidigital number, since it uses as much as digits as its factorization.
211243240057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 211243240057 its reverse (750042342112), we get a palindrome (961285582169).
The spelling of 211243240057 in words is "two hundred eleven billion, two hundred forty-three million, two hundred forty thousand, fifty-seven".
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