Base | Representation |
---|---|
bin | 1001100110110101100011… |
… | …11110001111010000001101 |
3 | 2202210120221211101110022002 |
4 | 10303122301332033100031 |
5 | 10232110300032404430 |
6 | 112532552135402045 |
7 | 4310163634025045 |
oct | 463326176172015 |
9 | 82716854343262 |
10 | 21125635044365 |
11 | 6805371269305 |
12 | 2452358523325 |
13 | ba31a60410c7 |
14 | 5306b4178725 |
15 | 2697d614a845 |
hex | 1336b1f8f40d |
21125635044365 has 8 divisors (see below), whose sum is σ = 25351204919040. Its totient is φ = 16900212791632.
The previous prime is 21125635044361. The next prime is 21125635044373. The reversal of 21125635044365 is 56344053652112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21125635044365 - 22 = 21125635044361 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21125635044361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36590405 + ... + 37163274.
It is an arithmetic number, because the mean of its divisors is an integer number (3168900614880).
Almost surely, 221125635044365 is an apocalyptic number.
It is an amenable number.
21125635044365 is a deficient number, since it is larger than the sum of its proper divisors (4225569874675).
21125635044365 is an equidigital number, since it uses as much as digits as its factorization.
21125635044365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73810971.
The product of its (nonzero) digits is 2592000, while the sum is 47.
Adding to 21125635044365 its reverse (56344053652112), we get a palindrome (77469688696477).
The spelling of 21125635044365 in words is "twenty-one trillion, one hundred twenty-five billion, six hundred thirty-five million, forty-four thousand, three hundred sixty-five".
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