Base | Representation |
---|---|
bin | 110000000010010011001111… |
… | …011011010100100010010011 |
3 | 1000201000200011111110012210011 |
4 | 300002103033123110202103 |
5 | 210142323322314320423 |
6 | 2025153254412215351 |
7 | 62333226035402152 |
oct | 6002231733244223 |
9 | 1021020144405704 |
10 | 211264331401363 |
11 | 61351777476469 |
12 | 1b84053916a557 |
13 | 90b61aa924566 |
14 | 3a253690ad599 |
15 | 196570b808b0d |
hex | c024cf6d4893 |
211264331401363 has 4 divisors (see below), whose sum is σ = 212325961207600. Its totient is φ = 210202701595128.
The previous prime is 211264331401339. The next prime is 211264331401373. The reversal of 211264331401363 is 363104133462112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211264331401363 - 29 = 211264331400851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211264331401373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530814902820 + ... + 530814903217.
It is an arithmetic number, because the mean of its divisors is an integer number (53081490301900).
Almost surely, 2211264331401363 is an apocalyptic number.
211264331401363 is a deficient number, since it is larger than the sum of its proper divisors (1061629806237).
211264331401363 is a wasteful number, since it uses less digits than its factorization.
211264331401363 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1061629806236.
The product of its (nonzero) digits is 186624, while the sum is 40.
Adding to 211264331401363 its reverse (363104133462112), we get a palindrome (574368464863475).
The spelling of 211264331401363 in words is "two hundred eleven trillion, two hundred sixty-four billion, three hundred thirty-one million, four hundred one thousand, three hundred sixty-three".
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