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21130010401 is a prime number
BaseRepresentation
bin10011101011011100…
…100101111100100001
32000112120211202002211
4103223130211330201
5321233240313101
613412413242121
71345423060603
oct235334457441
960476752084
1021130010401
118a63381615
124118493341
131cb9835246
1410463d7173
1583a07dc51
hex4eb725f21

21130010401 has 2 divisors, whose sum is σ = 21130010402. Its totient is φ = 21130010400.

The previous prime is 21130010399. The next prime is 21130010417. The reversal of 21130010401 is 10401003112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17129574400 + 4000436001 = 130880^2 + 63249^2 .

It is a cyclic number.

It is not a de Polignac number, because 21130010401 - 21 = 21130010399 is a prime.

Together with 21130010399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (21130010441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565005200 + 10565005201.

It is an arithmetic number, because the mean of its divisors is an integer number (10565005201).

Almost surely, 221130010401 is an apocalyptic number.

It is an amenable number.

21130010401 is a deficient number, since it is larger than the sum of its proper divisors (1).

21130010401 is an equidigital number, since it uses as much as digits as its factorization.

21130010401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21130010401 its reverse (10401003112), we get a palindrome (31531013513).

The spelling of 21130010401 in words is "twenty-one billion, one hundred thirty million, ten thousand, four hundred one".