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21130033 = 191112107
BaseRepresentation
bin101000010011…
…0101100110001
31110202111221211
41100212230301
520402130113
62032520121
7344413411
oct120465461
943674854
1021130033
1110a22341
1270b0041
1344ba8a2
142b40641
151cc5b3d
hex1426b31

21130033 has 4 divisors (see below), whose sum is σ = 22242160. Its totient is φ = 20017908.

The previous prime is 21130027. The next prime is 21130037. The reversal of 21130033 is 33003112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21130033 - 25 = 21130001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21129995 and 21130022.

It is not an unprimeable number, because it can be changed into a prime (21130037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 556035 + ... + 556072.

It is an arithmetic number, because the mean of its divisors is an integer number (5560540).

Almost surely, 221130033 is an apocalyptic number.

It is an amenable number.

21130033 is a deficient number, since it is larger than the sum of its proper divisors (1112127).

21130033 is a wasteful number, since it uses less digits than its factorization.

21130033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1112126.

The product of its (nonzero) digits is 54, while the sum is 13.

The square root of 21130033 is about 4596.7415633250. The cubic root of 21130033 is about 276.4606926477.

Adding to 21130033 its reverse (33003112), we get a palindrome (54133145).

The spelling of 21130033 in words is "twenty-one million, one hundred thirty thousand, thirty-three".

Divisors: 1 19 1112107 21130033