211301431131253 has 2 divisors, whose sum is σ = 211301431131254. Its totient is φ = 211301431131252.

The previous prime is 211301431131191. The next prime is 211301431131281. The reversal of 211301431131253 is 352131134103112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114569150875204 + 96732280256049 = 10703698^2 + 9835257^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211301431131253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211301431131053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105650715565626 + 105650715565627.

It is an arithmetic number, because the mean of its divisors is an integer number (105650715565627).

Almost surely, 2^{211301431131253} is an apocalyptic number.

It is an amenable number.

211301431131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

211301431131253 is an equidigital number, since it uses as much as digits as its factorization.

211301431131253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 211301431131253 its reverse (352131134103112), we get a palindrome (563432565234365).

The spelling of 211301431131253 in words is "two hundred eleven trillion, three hundred one billion, four hundred thirty-one million, one hundred thirty-one thousand, two hundred fifty-three".