Base | Representation |
---|---|
bin | 11110101111111010101… |
… | …010010101011001001101 |
3 | 21111000002222220110210202 |
4 | 132233322222111121031 |
5 | 234104443243002023 |
6 | 4254414203143245 |
7 | 305442650401355 |
oct | 36577252253115 |
9 | 7430088813722 |
10 | 2113034344013 |
11 | 74515088951a |
12 | 2a162ab14b25 |
13 | 1243485abab8 |
14 | 743b2a59b65 |
15 | 39e716a0128 |
hex | 1ebfaa9564d |
2113034344013 has 4 divisors (see below), whose sum is σ = 2117074563168. Its totient is φ = 2108994124860.
The previous prime is 2113034343941. The next prime is 2113034344039. The reversal of 2113034344013 is 3104434303112.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113034344013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113034344073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2020108793 + ... + 2020109838.
It is an arithmetic number, because the mean of its divisors is an integer number (529268640792).
Almost surely, 22113034344013 is an apocalyptic number.
It is an amenable number.
2113034344013 is a deficient number, since it is larger than the sum of its proper divisors (4040219155).
2113034344013 is an equidigital number, since it uses as much as digits as its factorization.
2113034344013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4040219154.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 2113034344013 its reverse (3104434303112), we get a palindrome (5217468647125).
The spelling of 2113034344013 in words is "two trillion, one hundred thirteen billion, thirty-four million, three hundred forty-four thousand, thirteen".
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