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2113103 = 5034201
BaseRepresentation
bin1000000011111001001111
310222100122002
420003321033
51020104403
6113142515
723650436
oct10037117
93870562
102113103
111213673
1285aa3b
1358ca75
143d011d
152bb188
hex203e4f

2113103 has 4 divisors (see below), whose sum is σ = 2117808. Its totient is φ = 2108400.

The previous prime is 2113091. The next prime is 2113109. The reversal of 2113103 is 3013112.

2113103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113103 - 24 = 2113087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1598 + ... + 2603.

It is an arithmetic number, because the mean of its divisors is an integer number (529452).

22113103 is an apocalyptic number.

2113103 is a deficient number, since it is larger than the sum of its proper divisors (4705).

2113103 is an equidigital number, since it uses as much as digits as its factorization.

2113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4704.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 2113103 is about 1453.6516088802. The cubic root of 2113103 is about 128.3237046054.

Adding to 2113103 its reverse (3013112), we get a palindrome (5126215).

Subtracting 2113103 from its reverse (3013112), we obtain a palindrome (900009).

The spelling of 2113103 in words is "two million, one hundred thirteen thousand, one hundred three".

Divisors: 1 503 4201 2113103