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211311010020317 is a prime number
BaseRepresentation
bin110000000010111110101101…
…101100000111101111011101
31000201012010122121111202011012
4300002332231230013233131
5210144104422031122232
62025230534325105005
762336500550202224
oct6002765554075735
91021163577452135
10211311010020317
116136a5503207a9
121b8495a5858165
1390ba70953704c
143a27716659cbb
151966a3e7c59b2
hexc02fadb07bdd

211311010020317 has 2 divisors, whose sum is σ = 211311010020318. Its totient is φ = 211311010020316.

The previous prime is 211311010020221. The next prime is 211311010020349. The reversal of 211311010020317 is 713020010113112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 203119903056196 + 8191106964121 = 14252014^2 + 2862011^2 .

It is a cyclic number.

It is not a de Polignac number, because 211311010020317 - 224 = 211310993243101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211311010020292 and 211311010020301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211311010023317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655505010158 + 105655505010159.

It is an arithmetic number, because the mean of its divisors is an integer number (105655505010159).

Almost surely, 2211311010020317 is an apocalyptic number.

It is an amenable number.

211311010020317 is a deficient number, since it is larger than the sum of its proper divisors (1).

211311010020317 is an equidigital number, since it uses as much as digits as its factorization.

211311010020317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 211311010020317 its reverse (713020010113112), we get a palindrome (924331020133429).

The spelling of 211311010020317 in words is "two hundred eleven trillion, three hundred eleven billion, ten million, twenty thousand, three hundred seventeen".