Search a number
-
+
21131120013143 = 72431247347207
BaseRepresentation
bin1001100110111111110001…
…11001101110111101010111
32202211010010002022201221212
410303133320321232331113
510232203013210410033
6112535300313332035
74310446565343500
oct463377071567527
982733102281855
1021131120013143
1168077263a6558
12245342940701b
13ba386b4c116a
14530a747dbba7
15269a0794b748
hex1337f8e6ef57

21131120013143 has 6 divisors (see below), whose sum is σ = 24581098790856. Its totient is φ = 18112388582652.

The previous prime is 21131120013103. The next prime is 21131120013151. The reversal of 21131120013143 is 34131002113112.

It is a de Polignac number, because none of the positive numbers 2k-21131120013143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21131120013103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 215623673555 + ... + 215623673652.

It is an arithmetic number, because the mean of its divisors is an integer number (4096849798476).

Almost surely, 221131120013143 is an apocalyptic number.

21131120013143 is a deficient number, since it is larger than the sum of its proper divisors (3449978777713).

21131120013143 is an equidigital number, since it uses as much as digits as its factorization.

21131120013143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 431247347221 (or 431247347214 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 21131120013143 its reverse (34131002113112), we get a palindrome (55262122126255).

The spelling of 21131120013143 in words is "twenty-one trillion, one hundred thirty-one billion, one hundred twenty million, thirteen thousand, one hundred forty-three".

Divisors: 1 7 49 431247347207 3018731430449 21131120013143