Search a number
-
+
2113113103 is a prime number
BaseRepresentation
bin111110111110011…
…1000110000001111
312110021012021020021
41331330320300033
513311424104403
6545403203011
7103236110413
oct17574706017
95407167207
102113113103
11994885172
124ab816467
13278a2c6aa
14160900d43
15c57a78bd
hex7df38c0f

2113113103 has 2 divisors, whose sum is σ = 2113113104. Its totient is φ = 2113113102.

The previous prime is 2113113097. The next prime is 2113113113. The reversal of 2113113103 is 3013113112.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113113103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113113113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056556551 + 1056556552.

It is an arithmetic number, because the mean of its divisors is an integer number (1056556552).

Almost surely, 22113113103 is an apocalyptic number.

2113113103 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113113103 is an equidigital number, since it uses as much as digits as its factorization.

2113113103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 2113113103 is about 45968.6099746338. The cubic root of 2113113103 is about 1283.2390911548.

Adding to 2113113103 its reverse (3013113112), we get a palindrome (5126226215).

Subtracting 2113113103 from its reverse (3013113112), we obtain a palindrome (900000009).

The spelling of 2113113103 in words is "two billion, one hundred thirteen million, one hundred thirteen thousand, one hundred three".