Base | Representation |
---|---|
bin | 1100010011001100100… |
… | …0101100000110110011 |
3 | 202012102122111221100012 |
4 | 3010303020230012303 |
5 | 11430231144011311 |
6 | 241024114445135 |
7 | 21160330345616 |
oct | 3046310540663 |
9 | 665378457305 |
10 | 211311313331 |
11 | 81686800338 |
12 | 34b538937ab |
13 | 16c078a5ba1 |
14 | a32846c17d |
15 | 576b50978b |
hex | 313322c1b3 |
211311313331 has 2 divisors, whose sum is σ = 211311313332. Its totient is φ = 211311313330.
The previous prime is 211311313253. The next prime is 211311313357. The reversal of 211311313331 is 133313113112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211311313331 - 210 = 211311312307 is a prime.
It is a super-2 number, since 2×2113113133312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211311313297 and 211311313306.
It is not a weakly prime, because it can be changed into another prime (211311313231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655656665 + 105655656666.
It is an arithmetic number, because the mean of its divisors is an integer number (105655656666).
Almost surely, 2211311313331 is an apocalyptic number.
211311313331 is a deficient number, since it is larger than the sum of its proper divisors (1).
211311313331 is an equidigital number, since it uses as much as digits as its factorization.
211311313331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 486, while the sum is 23.
Adding to 211311313331 its reverse (133313113112), we get a palindrome (344624426443).
The spelling of 211311313331 in words is "two hundred eleven billion, three hundred eleven million, three hundred thirteen thousand, three hundred thirty-one".
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