Base | Representation |
---|---|
bin | 11110101111111111110… |
… | …110100010111011101101 |
3 | 21111000100001202222001222 |
4 | 132233333312202323231 |
5 | 234110133041300102 |
6 | 4254430553513125 |
7 | 305445055543163 |
oct | 36577766427355 |
9 | 7430301688058 |
10 | 2113121431277 |
11 | 745195a6046a |
12 | 2a16541127a5 |
13 | 12436065101c |
14 | 743c0449233 |
15 | 39e79153aa2 |
hex | 1ebffda2eed |
2113121431277 has 2 divisors, whose sum is σ = 2113121431278. Its totient is φ = 2113121431276.
The previous prime is 2113121431273. The next prime is 2113121431301. The reversal of 2113121431277 is 7721341213112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1993591506916 + 119529924361 = 1411946^2 + 345731^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113121431277 - 22 = 2113121431273 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113121431273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056560715638 + 1056560715639.
It is an arithmetic number, because the mean of its divisors is an integer number (1056560715639).
Almost surely, 22113121431277 is an apocalyptic number.
It is an amenable number.
2113121431277 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113121431277 is an equidigital number, since it uses as much as digits as its factorization.
2113121431277 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14112, while the sum is 35.
Adding to 2113121431277 its reverse (7721341213112), we get a palindrome (9834462644389).
The spelling of 2113121431277 in words is "two trillion, one hundred thirteen billion, one hundred twenty-one million, four hundred thirty-one thousand, two hundred seventy-seven".
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