Base | Representation |
---|---|
bin | 110000000010111111111011… |
… | …111101111000101010100000 |
3 | 1000201012021001010200021012110 |
4 | 300002333323331320222200 |
5 | 210144120114231100000 |
6 | 2025231312521155320 |
7 | 62336545234662036 |
oct | 6002777375705240 |
9 | 1021167033607173 |
10 | 211312323300000 |
11 | 6137006466920a |
12 | 1b8498b162bb40 |
13 | 90ba888641610 |
14 | 3a277dcc36556 |
15 | 1966ab9c3a850 |
hex | c02ffbf78aa0 |
211312323300000 has 288 divisors, whose sum is σ = 746656828654464. Its totient is φ = 52015340160000.
The previous prime is 211312323299977. The next prime is 211312323300031. The reversal of 211312323300000 is 3323213112.
It is a self number, because there is not a number n which added to its sum of digits gives 211312323300000.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23191324 + ... + 30991323.
It is an arithmetic number, because the mean of its divisors is an integer number (2592558432828).
Almost surely, 2211312323300000 is an apocalyptic number.
211312323300000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211312323300000 is an abundant number, since it is smaller than the sum of its proper divisors (535344505354464).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211312323300000 is an equidigital number, since it uses as much as digits as its factorization.
211312323300000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54182698 (or 54182670 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 211312323300000 its reverse (3323213112), we get a palindrome (211315646513112).
The spelling of 211312323300000 in words is "two hundred eleven trillion, three hundred twelve billion, three hundred twenty-three million, three hundred thousand".
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