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2113130114 = 21056565057
BaseRepresentation
bin111110111110011…
…1100111010000010
312110021020010120022
41331330330322002
513311430130424
6545403413442
7103236211124
oct17574747202
95407203508
102113130114
11994896a27
124ab824282
13278a37364
14160907214
15c57ac95e
hex7df3ce82

2113130114 has 4 divisors (see below), whose sum is σ = 3169695174. Its totient is φ = 1056565056.

The previous prime is 2113130101. The next prime is 2113130143. The reversal of 2113130114 is 4110313112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1140750625 + 972379489 = 33775^2 + 31183^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2113130092 and 2113130101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528282527 + ... + 528282530.

Almost surely, 22113130114 is an apocalyptic number.

2113130114 is a deficient number, since it is larger than the sum of its proper divisors (1056565060).

2113130114 is a wasteful number, since it uses less digits than its factorization.

2113130114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1056565059.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 2113130114 is about 45968.7950026972. The cubic root of 2113130114 is about 1283.2425345928.

Adding to 2113130114 its reverse (4110313112), we get a palindrome (6223443226).

The spelling of 2113130114 in words is "two billion, one hundred thirteen million, one hundred thirty thousand, one hundred fourteen".

Divisors: 1 2 1056565057 2113130114