Base | Representation |
---|---|
bin | 1100010011001101001… |
… | …0111111011110111111 |
3 | 202012102211121011011021 |
4 | 3010303102333132333 |
5 | 11430232341423033 |
6 | 241024252405011 |
7 | 21160362324661 |
oct | 3046322773677 |
9 | 665384534137 |
10 | 211314014143 |
11 | 81688285511 |
12 | 34b54776767 |
13 | 16c083102bb |
14 | a328972531 |
15 | 576b88eb2d |
hex | 31334bf7bf |
211314014143 has 2 divisors, whose sum is σ = 211314014144. Its totient is φ = 211314014142.
The previous prime is 211314014141. The next prime is 211314014183. The reversal of 211314014143 is 341410413112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211314014143 - 21 = 211314014141 is a prime.
It is a super-2 number, since 2×2113140141432 (a number of 23 digits) contains 22 as substring.
Together with 211314014141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211314014141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105657007071 + 105657007072.
It is an arithmetic number, because the mean of its divisors is an integer number (105657007072).
Almost surely, 2211314014143 is an apocalyptic number.
211314014143 is a deficient number, since it is larger than the sum of its proper divisors (1).
211314014143 is an equidigital number, since it uses as much as digits as its factorization.
211314014143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 211314014143 its reverse (341410413112), we get a palindrome (552724427255).
The spelling of 211314014143 in words is "two hundred eleven billion, three hundred fourteen million, fourteen thousand, one hundred forty-three".
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