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211314014143 is a prime number
BaseRepresentation
bin1100010011001101001…
…0111111011110111111
3202012102211121011011021
43010303102333132333
511430232341423033
6241024252405011
721160362324661
oct3046322773677
9665384534137
10211314014143
1181688285511
1234b54776767
1316c083102bb
14a328972531
15576b88eb2d
hex31334bf7bf

211314014143 has 2 divisors, whose sum is σ = 211314014144. Its totient is φ = 211314014142.

The previous prime is 211314014141. The next prime is 211314014183. The reversal of 211314014143 is 341410413112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211314014143 - 21 = 211314014141 is a prime.

It is a super-2 number, since 2×2113140141432 (a number of 23 digits) contains 22 as substring.

Together with 211314014141, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211314014141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105657007071 + 105657007072.

It is an arithmetic number, because the mean of its divisors is an integer number (105657007072).

Almost surely, 2211314014143 is an apocalyptic number.

211314014143 is a deficient number, since it is larger than the sum of its proper divisors (1).

211314014143 is an equidigital number, since it uses as much as digits as its factorization.

211314014143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 211314014143 its reverse (341410413112), we get a palindrome (552724427255).

The spelling of 211314014143 in words is "two hundred eleven billion, three hundred fourteen million, fourteen thousand, one hundred forty-three".