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21131431341133 is a prime number
BaseRepresentation
bin1001100111000000010110…
…11101010110110001001101
32202211010220210010211200011
410303200023131112301031
510232204132410404013
6112535351234233221
74310460365523331
oct463401335266115
982733823124604
1021131431341133
116807876107913
1224534b5725811
13ba38bab570c9
14530aa3cbd7c1
15269a24e46c3d
hex13380b756c4d

21131431341133 has 2 divisors, whose sum is σ = 21131431341134. Its totient is φ = 21131431341132.

The previous prime is 21131431341121. The next prime is 21131431341173. The reversal of 21131431341133 is 33114313413112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18867017329924 + 2264414011209 = 4343618^2 + 1504797^2 .

It is a cyclic number.

It is not a de Polignac number, because 21131431341133 - 213 = 21131431332941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21131431341095 and 21131431341104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21131431341103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565715670566 + 10565715670567.

It is an arithmetic number, because the mean of its divisors is an integer number (10565715670567).

Almost surely, 221131431341133 is an apocalyptic number.

It is an amenable number.

21131431341133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21131431341133 is an equidigital number, since it uses as much as digits as its factorization.

21131431341133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776, while the sum is 31.

Adding to 21131431341133 its reverse (33114313413112), we get a palindrome (54245744754245).

The spelling of 21131431341133 in words is "twenty-one trillion, one hundred thirty-one billion, four hundred thirty-one million, three hundred forty-one thousand, one hundred thirty-three".