Base | Representation |
---|---|
bin | 1001100111000000010110… |
… | …11101010110110000101111 |
3 | 2202211010220210010211122001 |
4 | 10303200023131112300233 |
5 | 10232204132410403403 |
6 | 112535351234233131 |
7 | 4310460365523256 |
oct | 463401335266057 |
9 | 82733823124561 |
10 | 21131431341103 |
11 | 6807876107896 |
12 | 24534b57257a7 |
13 | ba38bab570a5 |
14 | 530aa3cbd79d |
15 | 269a24e46c1d |
hex | 13380b756c2f |
21131431341103 has 2 divisors, whose sum is σ = 21131431341104. Its totient is φ = 21131431341102.
The previous prime is 21131431341079. The next prime is 21131431341121. The reversal of 21131431341103 is 30114313413112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21131431341103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21131431341133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565715670551 + 10565715670552.
It is an arithmetic number, because the mean of its divisors is an integer number (10565715670552).
Almost surely, 221131431341103 is an apocalyptic number.
21131431341103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21131431341103 is an equidigital number, since it uses as much as digits as its factorization.
21131431341103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 21131431341103 its reverse (30114313413112), we get a palindrome (51245744754215).
The spelling of 21131431341103 in words is "twenty-one trillion, one hundred thirty-one billion, four hundred thirty-one million, three hundred forty-one thousand, one hundred three".
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