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2113150431804 = 223176095869317
BaseRepresentation
bin11110110000000001100…
…101001011001000111100
321111000102002100100022120
4132300001211023020330
5234110213002304204
64254433511242540
7305445560206626
oct36600145131074
97430362310276
102113150431804
11745200368a45
122a1661979450
131243666660b9
14743c4237c16
1539e7b9816d9
hex1ec0194b23c

2113150431804 has 12 divisors (see below), whose sum is σ = 4930684340904. Its totient is φ = 704383477264.

The previous prime is 2113150431793. The next prime is 2113150431811. The reversal of 2113150431804 is 4081340513112.

It is a tau number, because it is divible by the number of its divisors (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88047934647 + ... + 88047934670.

It is an arithmetic number, because the mean of its divisors is an integer number (410890361742).

Almost surely, 22113150431804 is an apocalyptic number.

It is an amenable number.

2113150431804 is an abundant number, since it is smaller than the sum of its proper divisors (2817533909100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2113150431804 is a wasteful number, since it uses less digits than its factorization.

2113150431804 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176095869324 (or 176095869322 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 33.

Adding to 2113150431804 its reverse (4081340513112), we get a palindrome (6194490944916).

The spelling of 2113150431804 in words is "two trillion, one hundred thirteen billion, one hundred fifty million, four hundred thirty-one thousand, eight hundred four".

Divisors: 1 2 3 4 6 12 176095869317 352191738634 528287607951 704383477268 1056575215902 2113150431804