Search a number
-
+
2113201103 = 13162553931
BaseRepresentation
bin111110111110100…
…1110001111001111
312110021100201221112
41331331032033033
513311434413403
6545405122235
7103236625106
oct17575161717
95407321845
102113201103
119949352a2
124ab85937b
13278a60770
1416092503d
15c57c39d8
hex7df4e3cf

2113201103 has 4 divisors (see below), whose sum is σ = 2275755048. Its totient is φ = 1950647160.

The previous prime is 2113201093. The next prime is 2113201117. The reversal of 2113201103 is 3011023112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113201103 - 212 = 2113197007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113201193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81276953 + ... + 81276978.

It is an arithmetic number, because the mean of its divisors is an integer number (568938762).

Almost surely, 22113201103 is an apocalyptic number.

2113201103 is a deficient number, since it is larger than the sum of its proper divisors (162553945).

2113201103 is a wasteful number, since it uses less digits than its factorization.

2113201103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162553944.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 2113201103 is about 45969.5671395762. The cubic root of 2113201103 is about 1283.2569042844.

Adding to 2113201103 its reverse (3011023112), we get a palindrome (5124224215).

The spelling of 2113201103 in words is "two billion, one hundred thirteen million, two hundred one thousand, one hundred three".

Divisors: 1 13 162553931 2113201103