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211321000001 = 661319698941
BaseRepresentation
bin1100010011001110110…
…1101001000001000001
3202012110022202001221202
43010303231221001001
511430241134000001
6241025102230545
721160505601626
oct3046355510101
9665408661852
10211321000001
1181691217051
1234b56b85455
1316c098b7c47
14a32987034d
15576c2be96b
hex3133b69041

211321000001 has 4 divisors (see below), whose sum is σ = 211640699604. Its totient is φ = 211001300400.

The previous prime is 211320999961. The next prime is 211321000021. The reversal of 211321000001 is 100000123112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 161334772225 + 49986227776 = 401665^2 + 223576^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211321000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211321000021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159848810 + ... + 159850131.

It is an arithmetic number, because the mean of its divisors is an integer number (52910174901).

Almost surely, 2211321000001 is an apocalyptic number.

It is an amenable number.

211321000001 is a deficient number, since it is larger than the sum of its proper divisors (319699603).

211321000001 is an equidigital number, since it uses as much as digits as its factorization.

211321000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 319699602.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 211321000001 its reverse (100000123112), we get a palindrome (311321123113).

The spelling of 211321000001 in words is "two hundred eleven billion, three hundred twenty-one million, one", and thus it is an aban number.

Divisors: 1 661 319698941 211321000001