Base | Representation |
---|---|
bin | 1001100111000001100111… |
… | …01101011110100111101011 |
3 | 2202211012122211212101211121 |
4 | 10303200303231132213223 |
5 | 10232212023300444420 |
6 | 112535542240440111 |
7 | 4310513205564121 |
oct | 463406355364753 |
9 | 82735584771747 |
10 | 21132106656235 |
11 | 6808092327073 |
12 | 2453663919037 |
13 | ba3997a32843 |
14 | 530b2986d911 |
15 | 269a643902aa |
hex | 133833b5e9eb |
21132106656235 has 32 divisors (see below), whose sum is σ = 25839305856000. Its totient is φ = 16588126464000.
The previous prime is 21132106656209. The next prime is 21132106656247. The reversal of 21132106656235 is 53265660123112.
It is not a de Polignac number, because 21132106656235 - 241 = 18933083400683 is a prime.
It is a super-3 number, since 3×211321066562353 (a number of 41 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21132106656191 and 21132106656200.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44278752 + ... + 44753458.
It is an arithmetic number, because the mean of its divisors is an integer number (807478308000).
Almost surely, 221132106656235 is an apocalyptic number.
21132106656235 is a deficient number, since it is larger than the sum of its proper divisors (4707199199765).
21132106656235 is a wasteful number, since it uses less digits than its factorization.
21132106656235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 475491.
The product of its (nonzero) digits is 388800, while the sum is 43.
Adding to 21132106656235 its reverse (53265660123112), we get a palindrome (74397766779347).
The spelling of 21132106656235 in words is "twenty-one trillion, one hundred thirty-two billion, one hundred six million, six hundred fifty-six thousand, two hundred thirty-five".
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