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211323012113 is a prime number
BaseRepresentation
bin1100010011001111010…
…1010100010000010001
3202012110110112022001102
43010303311110100101
511430242142341423
6241025213314145
721160531652063
oct3046365242021
9665413468042
10211323012113
1181692370854
1234b57795955
1316c0a140a45
14a329c35733
15576c56ac28
hex3133d54411

211323012113 has 2 divisors, whose sum is σ = 211323012114. Its totient is φ = 211323012112.

The previous prime is 211323012107. The next prime is 211323012119. The reversal of 211323012113 is 311210323112.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (211323012107) and next prime (211323012119).

It can be written as a sum of positive squares in only one way, i.e., 206562978064 + 4760034049 = 454492^2 + 68993^2 .

It is a cyclic number.

It is not a de Polignac number, because 211323012113 - 26 = 211323012049 is a prime.

It is a super-2 number, since 2×2113230121132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211323012119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105661506056 + 105661506057.

It is an arithmetic number, because the mean of its divisors is an integer number (105661506057).

Almost surely, 2211323012113 is an apocalyptic number.

It is an amenable number.

211323012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211323012113 is an equidigital number, since it uses as much as digits as its factorization.

211323012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 211323012113 its reverse (311210323112), we get a palindrome (522533335225).

The spelling of 211323012113 in words is "two hundred eleven billion, three hundred twenty-three million, twelve thousand, one hundred thirteen".