Base | Representation |
---|---|
bin | 110000000011001010000101… |
… | …100010000100110011100111 |
3 | 1000201020022011121222221201012 |
4 | 300003022011202010303213 |
5 | 210144304424111400403 |
6 | 2025240314141052435 |
7 | 62340412264415405 |
oct | 6003120542046347 |
9 | 1021208147887635 |
10 | 211323221200103 |
11 | 61374747200921 |
12 | 1b84ba3325711b |
13 | 90bb90436b70c |
14 | 3a2815432a475 |
15 | 196700685ced8 |
hex | c03285884ce7 |
211323221200103 has 2 divisors, whose sum is σ = 211323221200104. Its totient is φ = 211323221200102.
The previous prime is 211323221199949. The next prime is 211323221200109. The reversal of 211323221200103 is 301002122323112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211323221200103 - 238 = 211048343293159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211323221200109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105661610600051 + 105661610600052.
It is an arithmetic number, because the mean of its divisors is an integer number (105661610600052).
Almost surely, 2211323221200103 is an apocalyptic number.
211323221200103 is a deficient number, since it is larger than the sum of its proper divisors (1).
211323221200103 is an equidigital number, since it uses as much as digits as its factorization.
211323221200103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 211323221200103 its reverse (301002122323112), we get a palindrome (512325343523215).
The spelling of 211323221200103 in words is "two hundred eleven trillion, three hundred twenty-three billion, two hundred twenty-one million, two hundred thousand, one hundred three".
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