Base | Representation |
---|---|
bin | 10011101011100101… |
… | …110000100100101111 |
3 | 2000112202100211011112 |
4 | 103223211300210233 |
5 | 321234344210411 |
6 | 13412540542235 |
7 | 1345452356126 |
oct | 235345604457 |
9 | 60482324145 |
10 | 21132413231 |
11 | 8a64772926 |
12 | 411925197b |
13 | 1cba196b37 |
14 | 1046860abd |
15 | 83a3a5b8b |
hex | 4eb97092f |
21132413231 has 2 divisors, whose sum is σ = 21132413232. Its totient is φ = 21132413230.
The previous prime is 21132413209. The next prime is 21132413257. The reversal of 21132413231 is 13231423112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21132413231 is a prime.
It is a super-2 number, since 2×211324132312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21132413197 and 21132413206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21132493231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566206615 + 10566206616.
It is an arithmetic number, because the mean of its divisors is an integer number (10566206616).
Almost surely, 221132413231 is an apocalyptic number.
21132413231 is a deficient number, since it is larger than the sum of its proper divisors (1).
21132413231 is an equidigital number, since it uses as much as digits as its factorization.
21132413231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 864, while the sum is 23.
Adding to 21132413231 its reverse (13231423112), we get a palindrome (34363836343).
The spelling of 21132413231 in words is "twenty-one billion, one hundred thirty-two million, four hundred thirteen thousand, two hundred thirty-one".
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