Base | Representation |
---|---|
bin | 11110110000001011001… |
… | …101111110010110000111 |
3 | 21111000211100121001220111 |
4 | 132300023031332112013 |
5 | 234111030400402442 |
6 | 4254501525013451 |
7 | 305452562436424 |
oct | 36601315762607 |
9 | 7430740531814 |
10 | 2113312122247 |
11 | 745283665407 |
12 | 2a16a7b54287 |
13 | 124390cc9111 |
14 | 743db8c6d4b |
15 | 39e8ac6eb17 |
hex | 1ec0b37e587 |
2113312122247 has 2 divisors, whose sum is σ = 2113312122248. Its totient is φ = 2113312122246.
The previous prime is 2113312122193. The next prime is 2113312122253. The reversal of 2113312122247 is 7422212133112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113312122247 - 231 = 2111164638599 is a prime.
It is a super-2 number, since 2×21133121222472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113312122847) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056656061123 + 1056656061124.
It is an arithmetic number, because the mean of its divisors is an integer number (1056656061124).
Almost surely, 22113312122247 is an apocalyptic number.
2113312122247 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113312122247 is an equidigital number, since it uses as much as digits as its factorization.
2113312122247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8064, while the sum is 31.
Adding to 2113312122247 its reverse (7422212133112), we get a palindrome (9535524255359).
The spelling of 2113312122247 in words is "two trillion, one hundred thirteen billion, three hundred twelve million, one hundred twenty-two thousand, two hundred forty-seven".
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