211335303533141 has 2 divisors, whose sum is σ = 211335303533142. Its totient is φ = 211335303533140.

The previous prime is 211335303533087. The next prime is 211335303533143. The reversal of 211335303533141 is 141335303533112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 209667793608100 + 1667509925041 = 14479910^2 + 1291321^2 .

It is a cyclic number.

It is not a de Polignac number, because 211335303533141 - 2¹⁰ = 211335303532117 is a prime.

It is a super-2 number, since 2×211335303533141² (a number of 29 digits) contains 22 as substring.

Together with 211335303533143, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 211335303533095 and 211335303533104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211335303533143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105667651766570 + 105667651766571.

It is an arithmetic number, because the mean of its divisors is an integer number (105667651766571).

Almost surely, 2^{211335303533141} is an apocalyptic number.

It is an amenable number.

211335303533141 is a deficient number, since it is larger than the sum of its proper divisors (1).

211335303533141 is an equidigital number, since it uses as much as digits as its factorization.

211335303533141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 38.

The spelling of 211335303533141 in words is "two hundred eleven trillion, three hundred thirty-five billion, three hundred three million, five hundred thirty-three thousand, one hundred forty-one".