21134100113 has 4 divisors (see below), whose sum is σ = 24153257280. Its totient is φ = 18114942948.

The previous prime is 21134100101. The next prime is 21134100131. The reversal of 21134100113 is 31100143112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21134100113 - 2⁶ = 21134100049 is a prime.

It is a super-2 number, since 2×21134100113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21134100091 and 21134100100.

It is not an unprimeable number, because it can be changed into a prime (21134106113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1509578573 + ... + 1509578586.

It is an arithmetic number, because the mean of its divisors is an integer number (6038314320).

Almost surely, 2^21134100113 is an apocalyptic number.

It is an amenable number.

21134100113 is a deficient number, since it is larger than the sum of its proper divisors (3019157167).

21134100113 is an equidigital number, since it uses as much as digits as its factorization.

21134100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3019157166.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21134100113 its reverse (31100143112), we get a palindrome (52234243225).

The spelling of 21134100113 in words is "twenty-one billion, one hundred thirty-four million, one hundred thousand, one hundred thirteen".