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2113411302 = 232467251417
BaseRepresentation
bin111110111111000…
…0001100011100110
312110021202102021200
41331332001203212
513312013130202
6545413423330
7103241461662
oct17576014346
95407672250
102113411302
11994a69212
124ab93ab46
13278b05342
1416097b8a2
15c5815e1c
hex7df818e6

2113411302 has 24 divisors (see below), whose sum is σ = 4588881336. Its totient is φ = 702959136.

The previous prime is 2113411291. The next prime is 2113411303. The reversal of 2113411302 is 2031143112.

2113411302 is a `hidden beast` number, since 21 + 1 + 341 + 1 + 302 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113411303) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 117303 + ... + 134114.

It is an arithmetic number, because the mean of its divisors is an integer number (191203389).

Almost surely, 22113411302 is an apocalyptic number.

2113411302 is an abundant number, since it is smaller than the sum of its proper divisors (2475470034).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2113411302 is a wasteful number, since it uses less digits than its factorization.

2113411302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 251892 (or 251889 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 2113411302 is about 45971.8533670332. The cubic root of 2113411302 is about 1283.2994511697.

Adding to 2113411302 its reverse (2031143112), we get a palindrome (4144554414).

The spelling of 2113411302 in words is "two billion, one hundred thirteen million, four hundred eleven thousand, three hundred two".

Divisors: 1 2 3 6 9 18 467 934 1401 2802 4203 8406 251417 502834 754251 1508502 2262753 4525506 117411739 234823478 352235217 704470434 1056705651 2113411302