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2113430175509 is a prime number
BaseRepresentation
bin11110110000010010010…
…000010011111100010101
321111001010120201210112112
4132300102100103330111
5234111301111104014
64254521343200405
7305455525042142
oct36602220237425
97431116653475
102113430175509
11745334267594
122a171b5a6105
131243ac5c0c13
147440d4573c9
1539e962dd73e
hex1ec12413f15

2113430175509 has 2 divisors, whose sum is σ = 2113430175510. Its totient is φ = 2113430175508.

The previous prime is 2113430175497. The next prime is 2113430175511. The reversal of 2113430175509 is 9055710343112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1987809550609 + 125620624900 = 1409897^2 + 354430^2 .

It is a cyclic number.

It is not a de Polignac number, because 2113430175509 - 224 = 2113413398293 is a prime.

Together with 2113430175511, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113430175539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056715087754 + 1056715087755.

It is an arithmetic number, because the mean of its divisors is an integer number (1056715087755).

Almost surely, 22113430175509 is an apocalyptic number.

It is an amenable number.

2113430175509 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113430175509 is an equidigital number, since it uses as much as digits as its factorization.

2113430175509 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 2113430175509 in words is "two trillion, one hundred thirteen billion, four hundred thirty million, one hundred seventy-five thousand, five hundred nine".