Base | Representation |
---|---|
bin | 11110110000110100011… |
… | …011001000001011100111 |
3 | 21111002121112102110110022 |
4 | 132300310123020023213 |
5 | 234113434334430023 |
6 | 4255054302145355 |
7 | 305505655503245 |
oct | 36606433101347 |
9 | 7432545373408 |
10 | 2114003436263 |
11 | 7455a8911904 |
12 | 2a185b58225b |
13 | 1244712b6a74 |
14 | 7446563d795 |
15 | 39ecb7c87c8 |
hex | 1ec346c82e7 |
2114003436263 has 4 divisors (see below), whose sum is σ = 2205916629168. Its totient is φ = 2022090243360.
The previous prime is 2114003436229. The next prime is 2114003436283. The reversal of 2114003436263 is 3626343004112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2114003436263 - 210 = 2114003435239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2114003436203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45956596418 + ... + 45956596463.
It is an arithmetic number, because the mean of its divisors is an integer number (551479157292).
Almost surely, 22114003436263 is an apocalyptic number.
2114003436263 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2114003436263 is a deficient number, since it is larger than the sum of its proper divisors (91913192905).
2114003436263 is an equidigital number, since it uses as much as digits as its factorization.
2114003436263 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91913192904.
The product of its (nonzero) digits is 62208, while the sum is 35.
The spelling of 2114003436263 in words is "two trillion, one hundred fourteen billion, three million, four hundred thirty-six thousand, two hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •