Base | Representation |
---|---|
bin | 1001100111010000111001… |
… | …10000010010111001000111 |
3 | 2202211222211122122021102201 |
4 | 10303220130300102321013 |
5 | 10232330324213001010 |
6 | 112543420334015331 |
7 | 4311223424321131 |
oct | 463503460227107 |
9 | 82758748567381 |
10 | 21140311453255 |
11 | 6810612763555 |
12 | 2455173647547 |
13 | ba46a481c517 |
14 | 5312a7408051 |
15 | 269d9484123a |
hex | 133a1cc12e47 |
21140311453255 has 4 divisors (see below), whose sum is σ = 25368373743912. Its totient is φ = 16912249162600.
The previous prime is 21140311453243. The next prime is 21140311453277. The reversal of 21140311453255 is 55235411304112.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 21140311453255 - 237 = 21002872499783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2114031145321 + ... + 2114031145330.
It is an arithmetic number, because the mean of its divisors is an integer number (6342093435978).
Almost surely, 221140311453255 is an apocalyptic number.
21140311453255 is a deficient number, since it is larger than the sum of its proper divisors (4228062290657).
21140311453255 is an equidigital number, since it uses as much as digits as its factorization.
21140311453255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4228062290656.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 21140311453255 its reverse (55235411304112), we get a palindrome (76375722757367).
The spelling of 21140311453255 in words is "twenty-one trillion, one hundred forty billion, three hundred eleven million, four hundred fifty-three thousand, two hundred fifty-five".
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