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211403141341 = 7251120320513
BaseRepresentation
bin1100010011100010011…
…0111111000011011101
3202012200001022021200121
43010320212333003131
511430423201010331
6241041154554541
721162524024020
oct3047046770335
9665601267617
10211403141341
1181723620057
1234b7a598a51
1316c20917ba2
14a3367331b7
1557745e7c11
hex31389bf0dd

211403141341 has 8 divisors (see below), whose sum is σ = 242566156224. Its totient is φ = 180480768000.

The previous prime is 211403141273. The next prime is 211403141347. The reversal of 211403141341 is 143141304112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211403141341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211403141347) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60158500 + ... + 60162013.

It is an arithmetic number, because the mean of its divisors is an integer number (30320769528).

Almost surely, 2211403141341 is an apocalyptic number.

It is an amenable number.

211403141341 is a deficient number, since it is larger than the sum of its proper divisors (31163014883).

211403141341 is a wasteful number, since it uses less digits than its factorization.

211403141341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120320771.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 211403141341 its reverse (143141304112), we get a palindrome (354544445453).

The spelling of 211403141341 in words is "two hundred eleven billion, four hundred three million, one hundred forty-one thousand, three hundred forty-one".

Divisors: 1 7 251 1757 120320513 842243591 30200448763 211403141341