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2114040113 is a prime number
BaseRepresentation
bin111111000000001…
…1011000100110001
312110022221100211222
41332000123010301
513312143240423
6545435114425
7103250021153
oct17600330461
95408840758
102114040113
11995358699
124abba2a15
13278c95613
14160aa2ad3
15c58dc3c8
hex7e01b131

2114040113 has 2 divisors, whose sum is σ = 2114040114. Its totient is φ = 2114040112.

The previous prime is 2114040053. The next prime is 2114040139. The reversal of 2114040113 is 3110404112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1989873664 + 124166449 = 44608^2 + 11143^2 .

It is a cyclic number.

It is not a de Polignac number, because 2114040113 - 220 = 2112991537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2114040091 and 2114040100.

It is not a weakly prime, because it can be changed into another prime (2114040163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057020056 + 1057020057.

It is an arithmetic number, because the mean of its divisors is an integer number (1057020057).

Almost surely, 22114040113 is an apocalyptic number.

It is an amenable number.

2114040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114040113 is an equidigital number, since it uses as much as digits as its factorization.

2114040113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 2114040113 is about 45978.6919452914. The cubic root of 2114040113 is about 1283.4267134765.

Adding to 2114040113 its reverse (3110404112), we get a palindrome (5224444225).

The spelling of 2114040113 in words is "two billion, one hundred fourteen million, forty thousand, one hundred thirteen".