211404412103 has 2 divisors, whose sum is σ = 211404412104. Its totient is φ = 211404412102.

The previous prime is 211404412013. The next prime is 211404412127. The reversal of 211404412103 is 301214404112.

Together with previous prime (211404412013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211404412103 is a prime.

It is a super-3 number, since 3×211404412103³ (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211404412603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105702206051 + 105702206052.

It is an arithmetic number, because the mean of its divisors is an integer number (105702206052).

Almost surely, 2^211404412103 is an apocalyptic number.

211404412103 is a deficient number, since it is larger than the sum of its proper divisors (1).

211404412103 is an equidigital number, since it uses as much as digits as its factorization.

211404412103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 211404412103 its reverse (301214404112), we get a palindrome (512618816215).

The spelling of 211404412103 in words is "two hundred eleven billion, four hundred four million, four hundred twelve thousand, one hundred three".