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211411012303 = 297290034907
BaseRepresentation
bin1100010011100100010…
…1000000101011001111
3202012200121010011121201
43010321011000223033
511430432204343203
6241042035410331
721162650645311
oct3047105005317
9665617104551
10211411012303
1181728006687
1234b811539a7
1316c2244266a
14a3377c17b1
15577514ee1d
hex3139140acf

211411012303 has 4 divisors (see below), whose sum is σ = 218701047240. Its totient is φ = 204120977368.

The previous prime is 211411012297. The next prime is 211411012313. The reversal of 211411012303 is 303210114112.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-211411012303 is a prime.

It is a super-2 number, since 2×2114110123032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211411012313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3645017425 + ... + 3645017482.

It is an arithmetic number, because the mean of its divisors is an integer number (54675261810).

Almost surely, 2211411012303 is an apocalyptic number.

211411012303 is a deficient number, since it is larger than the sum of its proper divisors (7290034937).

211411012303 is an equidigital number, since it uses as much as digits as its factorization.

211411012303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7290034936.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 211411012303 its reverse (303210114112), we get a palindrome (514621126415).

The spelling of 211411012303 in words is "two hundred eleven billion, four hundred eleven million, twelve thousand, three hundred three".

Divisors: 1 29 7290034907 211411012303