Base | Representation |
---|---|
bin | 1100010011100100011… |
… | …0010001001100111101 |
3 | 202012200121201221001221 |
4 | 3010321012101030331 |
5 | 11430432300422031 |
6 | 241042050433341 |
7 | 21162653521036 |
oct | 3047106211475 |
9 | 665617657057 |
10 | 211411342141 |
11 | 8172821147a |
12 | 34b81292851 |
13 | 16c2252982c |
14 | a337869a8d |
15 | 57751b7a11 |
hex | 313919133d |
211411342141 has 2 divisors, whose sum is σ = 211411342142. Its totient is φ = 211411342140.
The previous prime is 211411342139. The next prime is 211411342157. The reversal of 211411342141 is 141243114112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 170676396900 + 40734945241 = 413130^2 + 201829^2 .
It is a cyclic number.
It is not a de Polignac number, because 211411342141 - 21 = 211411342139 is a prime.
Together with 211411342139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211411342111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105705671070 + 105705671071.
It is an arithmetic number, because the mean of its divisors is an integer number (105705671071).
Almost surely, 2211411342141 is an apocalyptic number.
It is an amenable number.
211411342141 is a deficient number, since it is larger than the sum of its proper divisors (1).
211411342141 is an equidigital number, since it uses as much as digits as its factorization.
211411342141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 768, while the sum is 25.
Adding to 211411342141 its reverse (141243114112), we get a palindrome (352654456253).
The spelling of 211411342141 in words is "two hundred eleven billion, four hundred eleven million, three hundred forty-two thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •