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2114115250133 = 9112320653403
BaseRepresentation
bin11110110000111011000…
…101101010011111010101
321111002220022211012020202
4132300323011222133111
5234114202001001013
64255113334510245
7305511514061225
oct36607305523725
97432808735222
102114115250133
11745655a42267
122a1890b05385
1312448b505913
1474476428085
1539ed6513858
hex1ec3b16a7d5

2114115250133 has 4 divisors (see below), whose sum is σ = 2116435904448. Its totient is φ = 2111794595820.

The previous prime is 2114115250127. The next prime is 2114115250141. The reversal of 2114115250133 is 3310525114112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2114115250133 - 236 = 2045395773397 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2114115250096 and 2114115250105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2114115250633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1160325791 + ... + 1160327612.

It is an arithmetic number, because the mean of its divisors is an integer number (529108976112).

Almost surely, 22114115250133 is an apocalyptic number.

It is an amenable number.

2114115250133 is a deficient number, since it is larger than the sum of its proper divisors (2320654315).

2114115250133 is an equidigital number, since it uses as much as digits as its factorization.

2114115250133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2320654314.

The product of its (nonzero) digits is 3600, while the sum is 29.

The spelling of 2114115250133 in words is "two trillion, one hundred fourteen billion, one hundred fifteen million, two hundred fifty thousand, one hundred thirty-three".

Divisors: 1 911 2320653403 2114115250133