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21141299701 is a prime number
BaseRepresentation
bin10011101100000111…
…101010000111110101
32000120101002022010001
4103230013222013311
5321244133042301
613413455231301
71345621040164
oct235407520765
960511068101
1021141299701
118a69792415
124120218531
131cbbc888c2
141047ad53db
1583b05dc01
hex4ec1ea1f5

21141299701 has 2 divisors, whose sum is σ = 21141299702. Its totient is φ = 21141299700.

The previous prime is 21141299693. The next prime is 21141299717. The reversal of 21141299701 is 10799214112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18454950801 + 2686348900 = 135849^2 + 51830^2 .

It is a cyclic number.

It is not a de Polignac number, because 21141299701 - 23 = 21141299693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21141299761) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570649850 + 10570649851.

It is an arithmetic number, because the mean of its divisors is an integer number (10570649851).

Almost surely, 221141299701 is an apocalyptic number.

It is an amenable number.

21141299701 is a deficient number, since it is larger than the sum of its proper divisors (1).

21141299701 is an equidigital number, since it uses as much as digits as its factorization.

21141299701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 37.

It can be divided in two parts, 211412 and 99701, that added together give a palindrome (311113).

The spelling of 21141299701 in words is "twenty-one billion, one hundred forty-one million, two hundred ninety-nine thousand, seven hundred one".