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2114137373143 is a prime number
BaseRepresentation
bin11110110000111100011…
…010000011100111010111
321111002221212110011022111
4132300330122003213113
5234114223131420033
64255115445011451
7305512203111625
oct36607432034727
97432855404274
102114137373143
11745667482644
122a18983b3b87
13124492c80463
1474479346515
1539ed84337cd
hex1ec3c6839d7

2114137373143 has 2 divisors, whose sum is σ = 2114137373144. Its totient is φ = 2114137373142.

The previous prime is 2114137373113. The next prime is 2114137373203. The reversal of 2114137373143 is 3413737314112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2114137373143 - 25 = 2114137373111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2114137373096 and 2114137373105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2114137373113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057068686571 + 1057068686572.

It is an arithmetic number, because the mean of its divisors is an integer number (1057068686572).

Almost surely, 22114137373143 is an apocalyptic number.

2114137373143 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114137373143 is an equidigital number, since it uses as much as digits as its factorization.

2114137373143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 127008, while the sum is 40.

The spelling of 2114137373143 in words is "two trillion, one hundred fourteen billion, one hundred thirty-seven million, three hundred seventy-three thousand, one hundred forty-three".