Base | Representation |
---|---|
bin | 10011101100001010… |
… | …101101110101000111 |
3 | 2000120102121000201121 |
4 | 103230022231311013 |
5 | 321244334220234 |
6 | 13413524334411 |
7 | 1345630616233 |
oct | 235412556507 |
9 | 60512530647 |
10 | 21142101319 |
11 | 8a6a18a709 |
12 | 4120544407 |
13 | 1cbc1a9731 |
14 | 1047c635c3 |
15 | 83b16b4b4 |
hex | 4ec2add47 |
21142101319 has 2 divisors, whose sum is σ = 21142101320. Its totient is φ = 21142101318.
The previous prime is 21142101313. The next prime is 21142101349. The reversal of 21142101319 is 91310124112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21142101319 - 23 = 21142101311 is a prime.
It is a super-2 number, since 2×211421013192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21142101293 and 21142101302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21142101311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571050659 + 10571050660.
It is an arithmetic number, because the mean of its divisors is an integer number (10571050660).
Almost surely, 221142101319 is an apocalyptic number.
21142101319 is a deficient number, since it is larger than the sum of its proper divisors (1).
21142101319 is an equidigital number, since it uses as much as digits as its factorization.
21142101319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 21142101319 in words is "twenty-one billion, one hundred forty-two million, one hundred one thousand, three hundred nineteen".
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