Base | Representation |
---|---|
bin | 10011101100001010… |
… | …101101110100111111 |
3 | 2000120102121000201022 |
4 | 103230022231310333 |
5 | 321244334220221 |
6 | 13413524334355 |
7 | 1345630616222 |
oct | 235412556477 |
9 | 60512530638 |
10 | 21142101311 |
11 | 8a6a18a701 |
12 | 41205443bb |
13 | 1cbc1a9726 |
14 | 1047c635b9 |
15 | 83b16b4ab |
hex | 4ec2add3f |
21142101311 has 2 divisors, whose sum is σ = 21142101312. Its totient is φ = 21142101310.
The previous prime is 21142101307. The next prime is 21142101313. The reversal of 21142101311 is 11310124112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21142101311 - 22 = 21142101307 is a prime.
Together with 21142101313, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21142101311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21142101313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571050655 + 10571050656.
It is an arithmetic number, because the mean of its divisors is an integer number (10571050656).
Almost surely, 221142101311 is an apocalyptic number.
21142101311 is a deficient number, since it is larger than the sum of its proper divisors (1).
21142101311 is an equidigital number, since it uses as much as digits as its factorization.
21142101311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 21142101311 its reverse (11310124112), we get a palindrome (32452225423).
The spelling of 21142101311 in words is "twenty-one billion, one hundred forty-two million, one hundred one thousand, three hundred eleven".
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