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211421212017 = 370473737339
BaseRepresentation
bin1100010011100110101…
…1111010110101110001
3202012201022022100222220
43010321223322311301
511430442312241032
6241043042151253
721163133436141
oct3047153726561
9665638270886
10211421212017
11817328428a4
1234b84652529
1316c245a40b2
14a338cb8921
155775eb712c
hex3139afad71

211421212017 has 4 divisors (see below), whose sum is σ = 281894949360. Its totient is φ = 140947474676.

The previous prime is 211421211983. The next prime is 211421212033. The reversal of 211421212017 is 710212124112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211421212017 - 210 = 211421210993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (211421212087) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35236868667 + ... + 35236868672.

It is an arithmetic number, because the mean of its divisors is an integer number (70473737340).

Almost surely, 2211421212017 is an apocalyptic number.

It is an amenable number.

211421212017 is a deficient number, since it is larger than the sum of its proper divisors (70473737343).

211421212017 is an equidigital number, since it uses as much as digits as its factorization.

211421212017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70473737342.

The product of its (nonzero) digits is 448, while the sum is 24.

Adding to 211421212017 its reverse (710212124112), we get a palindrome (921633336129).

The spelling of 211421212017 in words is "two hundred eleven billion, four hundred twenty-one million, two hundred twelve thousand, seventeen".

Divisors: 1 3 70473737339 211421212017