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211422213253 is a prime number
BaseRepresentation
bin1100010011100110111…
…1101111010010000101
3202012201101012020102201
43010321233233102011
511430443041311003
6241043115434501
721163145106166
oct3047157572205
9665641166381
10211422213253
1181733367069
1234b84a55a31
1316c24864a44
14a33909976d
155776113b1d
hex3139bef485

211422213253 has 2 divisors, whose sum is σ = 211422213254. Its totient is φ = 211422213252.

The previous prime is 211422213203. The next prime is 211422213329. The reversal of 211422213253 is 352312224112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 161361283204 + 50060930049 = 401698^2 + 223743^2 .

It is a cyclic number.

It is not a de Polignac number, because 211422213253 - 217 = 211422082181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211422213203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105711106626 + 105711106627.

It is an arithmetic number, because the mean of its divisors is an integer number (105711106627).

Almost surely, 2211422213253 is an apocalyptic number.

It is an amenable number.

211422213253 is a deficient number, since it is larger than the sum of its proper divisors (1).

211422213253 is an equidigital number, since it uses as much as digits as its factorization.

211422213253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5760, while the sum is 28.

Adding to 211422213253 its reverse (352312224112), we get a palindrome (563734437365).

The spelling of 211422213253 in words is "two hundred eleven billion, four hundred twenty-two million, two hundred thirteen thousand, two hundred fifty-three".