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2114303032341 = 32234922559149
BaseRepresentation
bin11110110001000110010…
…001111111110000010101
321111010101102011112000100
4132301012101333300111
5234120043034013331
64255144123404313
7305516254151223
oct36610621776025
97433342145010
102114303032341
11745741a3a875
122a1923983699
131244bb3a2a56
1474493349b13
1539ee7c57ae6
hex1ec4647fc15

2114303032341 has 6 divisors (see below), whose sum is σ = 3053993268950. Its totient is φ = 1409535354888.

The previous prime is 2114303032333. The next prime is 2114303032381. The reversal of 2114303032341 is 1432303034112.

It is a happy number.

2114303032341 is a `hidden beast` number, since 2 + 1 + 14 + 3 + 0 + 303 + 2 + 341 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1578676654116 + 535626378225 = 1256454^2 + 731865^2 .

It is not a de Polignac number, because 2114303032341 - 23 = 2114303032333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2114303032321) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 117461279566 + ... + 117461279583.

Almost surely, 22114303032341 is an apocalyptic number.

It is an amenable number.

2114303032341 is a deficient number, since it is larger than the sum of its proper divisors (939690236609).

2114303032341 is a wasteful number, since it uses less digits than its factorization.

2114303032341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 234922559155 (or 234922559152 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 2114303032341 its reverse (1432303034112), we get a palindrome (3546606066453).

The spelling of 2114303032341 in words is "two trillion, one hundred fourteen billion, three hundred three million, thirty-two thousand, three hundred forty-one".

Divisors: 1 3 9 234922559149 704767677447 2114303032341