Base | Representation |
---|---|
bin | 111111000000101… |
… | …1111011011111001 |
3 | 12110100110120221122 |
4 | 1332001133123321 |
5 | 13312231220441 |
6 | 545445115025 |
7 | 103252265414 |
oct | 17601373371 |
9 | 5410416848 |
10 | 2114320121 |
11 | 99552a001 |
12 | 4b00b8a75 |
13 | 279062bc4 |
14 | 160b36b7b |
15 | c594534b |
hex | 7e05f6f9 |
2114320121 has 2 divisors, whose sum is σ = 2114320122. Its totient is φ = 2114320120.
The previous prime is 2114320079. The next prime is 2114320123. The reversal of 2114320121 is 1210234112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1860714496 + 253605625 = 43136^2 + 15925^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2114320121 is a prime.
Together with 2114320123, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2114320121.
It is not a weakly prime, because it can be changed into another prime (2114320123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057160060 + 1057160061.
It is an arithmetic number, because the mean of its divisors is an integer number (1057160061).
Almost surely, 22114320121 is an apocalyptic number.
It is an amenable number.
2114320121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114320121 is an equidigital number, since it uses as much as digits as its factorization.
2114320121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
The square root of 2114320121 is about 45981.7368201768. The cubic root of 2114320121 is about 1283.4833749498.
Adding to 2114320121 its reverse (1210234112), we get a palindrome (3324554233).
The spelling of 2114320121 in words is "two billion, one hundred fourteen million, three hundred twenty thousand, one hundred twenty-one".
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