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21143234013 = 3111555941179
BaseRepresentation
bin10011101100001111…
…000010010111011101
32000120111201120111020
4103230033002113131
5321300131442023
613414004514353
71345643344446
oct235417022735
960514646436
1021143234013
118a6a893720
1241209ab9b9
131cbc4b5175
14104807a2cd
1583b2e1de3
hex4ec3c25dd

21143234013 has 16 divisors (see below), whose sum is σ = 30756518400. Its totient is φ = 12812946480.

The previous prime is 21143233987. The next prime is 21143234053. The reversal of 21143234013 is 31043234112.

It is a happy number.

It is not a de Polignac number, because 21143234013 - 25 = 21143233981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21143234053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 492858 + ... + 534036.

It is an arithmetic number, because the mean of its divisors is an integer number (1922282400).

Almost surely, 221143234013 is an apocalyptic number.

It is an amenable number.

21143234013 is a deficient number, since it is larger than the sum of its proper divisors (9613284387).

21143234013 is a wasteful number, since it uses less digits than its factorization.

21143234013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56752.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 21143234013 its reverse (31043234112), we get a palindrome (52186468125).

Subtracting 21143234013 from its reverse (31043234112), we obtain a palindrome (9900000099).

The spelling of 21143234013 in words is "twenty-one billion, one hundred forty-three million, two hundred thirty-four thousand, thirteen".

Divisors: 1 3 11 33 15559 41179 46677 123537 171149 452969 513447 1358907 640704061 1922112183 7047744671 21143234013