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211433102030 = 2521143310203
BaseRepresentation
bin1100010011101001100…
…1010001101011001110
3202012202010200110000202
43010322121101223032
511431003333231110
6241044145053502
721163336466663
oct3047231215316
9665663613022
10211433102030
1181739523a57
1234b88627292
1316c26ba7cc7
14a33a6d1a6a
1557770650a5
hex313a651ace

211433102030 has 8 divisors (see below), whose sum is σ = 380579583672. Its totient is φ = 84573240808.

The previous prime is 211433102021. The next prime is 211433102051. The reversal of 211433102030 is 30201334112.

211433102030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 211433101993 and 211433102011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10571655092 + ... + 10571655111.

It is an arithmetic number, because the mean of its divisors is an integer number (47572447959).

Almost surely, 2211433102030 is an apocalyptic number.

211433102030 is a deficient number, since it is larger than the sum of its proper divisors (169146481642).

211433102030 is a wasteful number, since it uses less digits than its factorization.

211433102030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21143310210.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 211433102030 its reverse (30201334112), we get a palindrome (241634436142).

The spelling of 211433102030 in words is "two hundred eleven billion, four hundred thirty-three million, one hundred two thousand, thirty".

Divisors: 1 2 5 10 21143310203 42286620406 105716551015 211433102030