Base | Representation |
---|---|
bin | 10011101100001111… |
… | …011000001001001101 |
3 | 2000120111220002211221 |
4 | 103230033120021031 |
5 | 321300142320323 |
6 | 13414010443341 |
7 | 1345644165505 |
oct | 235417301115 |
9 | 60514802757 |
10 | 21143323213 |
11 | 8a6a944741 |
12 | 4120a33551 |
13 | 1cbc51694c |
14 | 10480a0a05 |
15 | 83b30d55d |
hex | 4ec3d824d |
21143323213 has 4 divisors (see below), whose sum is σ = 21635028448. Its totient is φ = 20651617980.
The previous prime is 21143323151. The next prime is 21143323217. The reversal of 21143323213 is 31232334112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21143323213 - 225 = 21109768781 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21143323217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245852553 + ... + 245852638.
It is an arithmetic number, because the mean of its divisors is an integer number (5408757112).
Almost surely, 221143323213 is an apocalyptic number.
It is an amenable number.
21143323213 is a deficient number, since it is larger than the sum of its proper divisors (491705235).
21143323213 is an equidigital number, since it uses as much as digits as its factorization.
21143323213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 491705234.
The product of its digits is 2592, while the sum is 25.
Adding to 21143323213 its reverse (31232334112), we get a palindrome (52375657325).
The spelling of 21143323213 in words is "twenty-one billion, one hundred forty-three million, three hundred twenty-three thousand, two hundred thirteen".
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